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x^2-49x+11=0
a = 1; b = -49; c = +11;
Δ = b2-4ac
Δ = -492-4·1·11
Δ = 2357
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-\sqrt{2357}}{2*1}=\frac{49-\sqrt{2357}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+\sqrt{2357}}{2*1}=\frac{49+\sqrt{2357}}{2} $
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